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Can you solve this question?

A wooden block 2 m × 1 m × 0·5 m and of specific gravity 0·76 is floating in water. What load may be placed on the block, so that it may completely inmerse in water.

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Solution:

Given: Volume of block = 2 × 1 × 0·5 = 1 m3 and specific gravity of wood = 0·76.
Let W =Weight placed on the block of wood.
We know that weight of the wooden block
=(9·8 × 0·76) 1 = 7·45 kN
∴ Total weight acting downwards
=7·45 + W ...(i)
and volume of water displaced when the block is completely immersed in it
=1 m3
∴ Upward thrust when the block is completely immersed
=9·8 × 1 = 9·8 kN ...(ii)
Now equating the total downward weight and upward thrust
7·45 + W = 9·8
W =9·8 – 7·45 = 2·35 kN Ans.

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